Steven Seagal – Biography, Facts & Life Story
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Height, Weight & Physical Stats
Body Measurements | 48-15-36 Inches |
Height | 6 feet 3 inches (1.93 m) |
Weight | 120 kg (265 lbs) |
Hair Color | Brown |
Eye Color | Brown |
Nickname | Steven |
Gender | Male |
Age | 72 years old (in 2024) |
Date of Birth | April 10, 1952 |
Full Name | Steven Frederic Seagal |
Profession | Actor, Producer, Screenwriter, Director |
Nationality | American, Serbian, Russian |
Birthplace | Lansing, Michigan, United States |
Published on | October 16, 2019 on 09:45 PM |
Zodiac Sign | Aries |
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Steven Seagal Education
School: Buena Park High School
College: Fullerton College
Steven Seagal Career
Profession: Actor, Producer, Screenwriter, Director
Debut:
Net Worth: USD $16 million Approx
Family & Relatives
Father: Samuel Steven Seagal
Mother: Patricia Seagal
Sister: Brenda Seagal
Marital Status: Married
Married: Erdenetuya Seagal (m. 2009), Adrienne La Russa (m. 1984–1987), Kelly LeBrock (m. 1987–1996), Miyako Fujitani (m. 1974–1987)
No. of Children: 7
Son: Kunzang Seagal, Dominic Seagal, Kentaro Seagal
Daughter: Ayako Fujitani, Arissa LeBrock, Annaliza Seagal
Past Relationships:
Arissa Wolf (1994 – 1996)
FAQs
Who is Steven Seagal?
Steven Seagal is an American, Serbian, Russian actor, producer, screenwriter, director, born on 10 April, 1952 in Lansing, Michigan, United States.
How old is Steven Seagal?
Steven Seagal is 0 years old as of November 2024.
How tall is Steven Seagal?
Steven Seagal is 6 feet 3 inches (1.93 m).